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DAY 3
30.4.20
GOOD MORNING BOYS,
Today you will attend the MCQ FIRST then you will  learn about Hydrogen spectrum and Bohrs theory.


LEARNING OUTCOMES:
Students will be able to
  • know different series in hydrogen spectrum
  • learn Rydbergs formula
  • understand Bohrs model for hydrogen atom.
Emission spectrum of Hydrogen atom

Spectral Lines for atomic hydrogen is given by
Rydberg equation
Rydberg equation
R = Rydberg’s constant = 109677 cm-1


Spectral Lines for atomic hydrogen

Bohr’s model for hydrogen atom:

Postulates 
1. Electron in hydrogen atom moves around the nucleus in circular path of fixed radius and energy. These paths are called orbits or energy levels.
2. As long as an electron remains in a particular orbit, it does not lose or gain energy and its energy remains constant.
3. However, when electron will move from a lower stationary state to a higher stationary state a certain amount of energy is absorbed by the electron or some energy is emitted when electron moves from higher stationary state to lower stationary state
4. Frequency of radiations emitted or absorbed when transition of an electron occurs, is given by
frequency accompaning electronic transition                                           Where, E1 & E2 represent the lower & higher energy states respectively.
5. An electron can move only in those orbits for which its angular momentum is an integral multiple of h/2Ï€, i.e.,
angular momentum of orbital
[Where n =1,2,3.....]
 Assumptions of Bohar’s model are:
1. The radii of the stationary states are expressed as:
radius of stationary orbital
2.  Energy of an electron in nth orbit is given as:
energy of electron in an orbit
Limitations of Bohr’s model of atom: 1. It failed to account for the finer details of the hydrogen spectrum.
2. It was unable to explain spectrum of atoms containing more than one electron.
3. It failed to explain splitting of the spectral lines in presence of electric (Stark effect) or magnetic field ( Zeeman effect).
4. It failed to explain formation of molecules from atoms by chemical bonding.


Dual behaviour of matter:
de Broglie proposed that matter exhibits dual behavior, i.e., matter shows both particle as well as wave nature and gave the following relation between wavelength (λ) and momentum (p) of a material particle.
 de broglie relation
[Where, m is the mass of the particle, v its velocity and p its momentum]
The above equation is named as de Broglie’s relation.
Heisenberg’s Uncertainty Principle:
It states that it is impossible to determine simultaneously, the exact position and exact momentum (or velocity) of an electron. The product of their uncertainties is always equal to or greater than h/4Ï€. I.e.,
 heisenberg uncertainty principal
Where, Δx = uncertainty in position
            Δp = uncertainty in momentum
  Significance of Uncertainty Principle
  • Heisenberg’s uncertainty principle rules out the existence of definite paths or trajectories of electrons and other similar particles
  • The effect of Heisenberg Uncertainty Principle is significant only for motion of microscopic objects and is negligible for that of macroscopic objects.
Reasons for the Failure of the Bohr Model:
1. It ignores the dual behavior of matter.
2. It contradicts Heisenberg’s uncertainty principle.
Thats all for the day
Take care
stay safe
MARK YOUR ATTENDANCE ON THE BLOG AS WELL AS FORM.

Comments

  1. Jaskeerat Singh (11-D) - Present

    ReplyDelete
  2. Good morning ma'am,
    Yumn Jame 11th D present.

    ReplyDelete
  3. Good morning ma'am. The test and attendance has been submitted. -SHAMBHAVA S. (11D)

    ReplyDelete
  4. Good morning ma'am
    Anugrah Singh 11D
    Present

    ReplyDelete
  5. Good Morning Maam
    Ratnango Ghosh
    11 D Present

    ReplyDelete
    Replies
    1. Ma'am the above test is an MCQ, but on a particular question more than one answers are possible.

      Delete
    2. ONLY ONE QUESTION HAS TWO ANSWERS FOR WHICH PARTICULAR CHOICE WAS GIVEN

      Delete
  6. Replies
    1. Ma'am, I had a doubt from the quiz.
      In the second question, when we use M1V1 = M2V2 then we get 200*.65 = x*.20 and the final volume comes as 650. But the question asks the amount of water that has to be added. So shouldn't the answer be 450 mL?

      Delete
    2. YES
      CORRECT
      THE ANSWER SHOULD BE 450 ML AS WATER QUANTITY IS ASKED

      Delete
  7. mam what is the difference between 1M and 1m

    ReplyDelete
  8. Good morning ma'am,
    Celestine Saji,
    The test and the attendance has been submitted

    ReplyDelete
  9. Good Morning Ma'am
    Soham Kulkarni
    11-D
    Present

    ReplyDelete
  10. Good evening
    BhumikTandon of class 11th D is present
    Attendence has been submitted on the form earlier

    ReplyDelete

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