Chemistry class 11 saj

DAY 4 1.5.20 Good Morning Boys, Today you will write the experiment for the detection of Nitrite and sulphite in your practical file. Learning Outcomes : Students will be able to Write the experiment. Identify the formula of Nitrite and Sulphite. Learn the test of detecting Nitrite And sulphite Refer to the images to write the experiment in the file in the given format. THATS ALL FOR THE DAY MARK YOUR ATTENDANCE ON THE FORM AND IN THE COMMENT SECTION OF THE BLOG. Loading…

DAY 3 30.4.20 GOOD MORNING BOYS, Today you will attend the MCQ FIRST then you will  learn about Hydrogen spectrum and Bohrs theory. Loading… LEARNING OUTCOMES: Students will be able to know different series in hydrogen spectrum learn Rydbergs formula understand Bohrs model for hydrogen atom. Emission spectrum of Hydrogen atom Spectral Lines for atomic hydrogen is given by Rydberg equation R = Rydberg’s constant = 109677 cm -1 B ohr’s model for hydrogen atom: Postulates  1. Electron in hydrogen atom moves around the nucleus in circular path of fixed radius and energy. These paths are called orbits or energy levels. 2. As long as an electron remains in a particular orbit, it does not lose or gain energy and its energy remains constant. 3. However, when electron will move from a lower stationary state to a higher stationary state a certain amount of energy is absorbed by the electron or some energy is emitted when electron moves fr...

DAY 2 29.4.20 Good Morning Boys, Today we will discuss about planks quantum theory , photoelectric effect, emmision and absorption spectra. Learning Outcomes, Students will be able to Define photoelectric effect. understand concept of emmission and absorption. Particle nature of Electromagnetic radiations : There were two important phenomenon that couldn’t be explained by considering Light with  wave character: The phenomenon is: Black body radiation Photoelectric effect Black body: An ideal body, which emits and absorbs all frequencies, is called a black body. The radiation emitted by such a body is called black body radiation. Photoelectric effect: The phenomenon of ejection of electrons from the surface of metal when light of suitable frequency strikes it is called photoelectric effect. The ejected electrons are called photoelectrons.   Number of electron ejected is directly proportional to intensity (or brightness) of light. There is...

DAY 1 28.4.20 6th period Good Morning Boys,  We have discussed some of the basic concepts of structure of atom in the 4 th period. We have revised the main points of Thomson model of atom , now would be discussing Rutherford  model of atom and about electromagnetic radiations. Note   :  Day 3 i.e 30.4.20 short assestment MCQ will be conducted on the topic of concentration of solution. Learning Objectives: students will be able to Describe Rutherford  model  of atom. List the merits and demerits of Rutherford models of atom. Define terms used in defining characteristics of wave. RUTHERFORD SCATTERING EXPERIMENT :   He took a Gold foil and passed Alpha rays through it. The source of these Alpha rays was radioactive substance.                   Observations  a. Most of the α- particles passed through gold foil undeflected b. A small fraction of α- particles got deflected ...

DAY 1 28.4.20  4 th period Good Morning Boys, Today we will start with new chapter i.e structure of atom. Learning Outcomes students will be able to Learn the properties of electron ,proton and neutron. know about the discoveries  of  subatomic particles Describe Thomsons model Note ; 1. Day 3 i.e 30.4.20 short assestment MCQ will be conducted on the topic of concentration of solution. 2.cathode ray experiment , discovery of electron, proton and neutron is for reading only. rest content to be noted in register. Atom is the smallest indivisible particle of the matter. Atom is made of electron, proton and neutrons. P ARTICLE ELE CTRON P ROTON NEUTRON Discovery Sir. J. J. Thomson (1869) Goldstein (1886) Chadwick (1932) Nature of charge Negative Positive Neutral Amount of charge 1.6 x 10 -19 Coloumb 1.6 x 10 -19 Coloumb 0 M ass 9.11 x 10 -31 kg 1.672614 x 10 -27 kg 1.67492 x10 -27 kg   El...

DAY 5 27.4.20 Good Morning Boys, Today we will be practising the numericals related to the concept learnt in previous classes. Learning outcome : students will be able to Apply the formula interpret the question. Analyse the question. Molarity formula with  Density  is given as conversion table for reference : 1 cm 3 1mL 1000 mm 3 1 Litre 1000mL 1000 cm 3 1 m 3 10 6   cm 3 1000 L 1 dm 3 1000 cm 3 1 L NUMERICAL QUESTIONS : Question 1 Calculate the molarity of  N a O H N a O H  in the solution prepared by dissolving its 4 g in enough water to form 250 mL of the solution. Solution  Molarity M = Moles of solute(g)/ volume of solution (litres) = (4 g / 40 g ) ×  (1000/250) =0.1 mol/0.250 L = 0.4 mol/L = 0.4 M Question 2 20% (w/W) NaOH solution (density of solution= 1.2 g/cc). Calculate the Molarity? Solution 20% (w/M) means 20 gm  in 100gm  of solution Now Density of solution =1.2g/cc Density = mass /...